# Which of the following statements are FALSE?

**Discipline:** Chemistry

**Type of Paper:** Question-Answer

**Academic Level:** Undergrad. (yrs 3-4)

**Paper Format:** APA

**Pages:**1

**Words:**275

Question

**Expert Answer**

**#(a):**
An enzyme catalyst only helps to reach the equilibrium faster without
disturbing the equilibrium cosntant. Since equilibrium constant remains
same, the equilibrium is not shifted by an enzyme. Hence **False.**

**#(b):**
Enzymes are special due to their ability to be specific towards a
single reactant or substrate due their ability to identify only the
substrate that are specific to them. On the other hand this property is
not found in a plane inorganic catalyst and substrates. Hence **True. **

**# (c): **According to Michaelis-Menten kinetics, the formula for Vmax of an enzyme catalyzed reaction is:

V = Vmax * [S] / (Km + [S]) ----- (1)

where V = observed rate

[S] = Substrate concentration

Given Km = [S] ------ (2)

From equation-(1) and (2), replacing [S] by Km

=> V = Vmax * [S] / (Km + [S])

=> V = Vmax * Km / (Km + Km)

=> V = Vmax * Km / 2Km

=> V = Vmax / 2 [ Km cancels out from numerator and denominator]

=> Vmax = 2*V

Hence Vmax is twice the rate observed. Hence **True.**

**#(d): **Lineweaver-Burk
plot of graphical representation of how the reciprocal of reaction
rate(1/V) varies with the reciprocal of substrate concentration
(1/[S]). The slope of the equation is the ratio of Km and Vmax i.e slope
= Km/Vmax. Hence we can find the ratio of product to reactants using
the slope of Lineweaver-Burk plot.

Hence **True.**

**#(e): **An
enzyme helps in reaching the reaction faster. So smaller the enzyme
concentration larger is the time required to achieve product. Since on
the separate experiment, we have decreased the enzyme concentration by
1/3rd, the time taken to form the same amount of product (12 micromoles)
will be 3 times higher.

Hence total time required = 9*3 = 27 minutes.

Hence **True**

**Hence only option (a) is False and rest are True. **